From Kirchoff's lope Rule

During the changing process: V_o = V_R + V_c
_{= I R + ∫I dt/C}
During the discharging process V_c = -V_R
_{= ∫I dt/C = -I R}

_{If the time interval dt is very small,integral become summation.}

_{During the charging process:}
 

_{1. Find current I => I = (Vo - Vc )/ R}

_{2. Then calculate new Vc => Vc = Vc + I *dt/C}

_{3. calculate VR = I * R}
 

You should be able to find out the rest.

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作者：國立台灣師範大學 物理系 黃福坤

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